CodeEngn Challenge

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최근 인증 기록을 확인할 수 있습니다. 공개 별칭과 코멘트만 표시됩니다.

Public record

최근 인증 페이지당 50건

24,520건의 공개 인증 기록 · 222 / 491 페이지

Checkin timeNameLevelCommentPoint
2018-12-14 23:38:34HiroBasic L03-5
2018-12-14 23:37:13HiroBasic L04-7
2018-12-14 23:29:38HiroBasic L02-3
2018-12-14 23:23:46HiroBasic L01-1
2018-12-11 23:15:01linexyBasic L09-17
2018-12-11 23:03:24linexyBasic L08-15
2018-12-11 22:40:38linexyBasic L07-13
2018-12-10 23:06:01linexyBasic L06-11
2018-12-10 22:58:49linexyBasic L05-9
2018-12-09 22:35:19tiger6853405Basic L01-1
2018-12-08 22:19:35linexyBasic L04-7
2018-12-08 22:14:48linexyBasic L03-5
2018-12-07 23:39:20linexyBasic L02JK3FJZh3
2018-12-07 16:11:40zhsks21c@naver.comAdvance L03-9
2018-12-06 18:46:30zhsks21c@naver.comAdvance L01-5
2018-12-05 22:56:02linexyBasic L01-1
2018-12-05 13:37:51junchicBasic L01-1
2018-12-05 01:32:13StarHoAdvance L06-15
2018-12-05 01:12:38StarHoAdvance L05-13
2018-12-05 00:40:29StarHoAdvance L04-11
2018-12-05 00:38:24StarHoAdvance L03-9
2018-12-04 17:07:45StarHoBasic L14-27
2018-12-04 15:53:23StarHoBasic L12-23
2018-12-04 14:52:25StarHoBasic L11-21
2018-12-04 14:44:47StarHoBasic L10-19
2018-12-04 13:58:42StarHoBasic L09-17
2018-12-04 13:42:04StarHoBasic L08-15
2018-12-04 09:46:21demasia13Crypto L01암호학 1번 문제 처음에는 알파벳만 있어서 ROT13 으로 된 암호인줄 알았지만 돌려보니 이상한 값이 나와서 아니라는 것을 알게 되었다. 그래서 카이사르 암호화를 응용해서 1부터 26까지 다 밀어보기로 했다. string = !eqbpntwemza! for i in range(26): str = !! print(!now : !, i+1) for j in string: crypted = ord(j)+i if crypted !! 122: crypted = crypted-26 str += chr(crypted) print(str) 이 코드로 실행을 해보니 19로 민 값인 withflowers가 나오게 됬다.5
2018-12-03 21:12:14StarHoBasic L07-13
2018-12-03 21:03:00StarHoBasic L06-11
2018-12-03 16:45:03StarHoBasic L05-9
2018-12-03 16:31:31StarHoBasic L04-7
2018-12-01 22:28:25gatojBasic L16-31
2018-12-01 22:23:58gatojBasic L15-29
2018-12-01 21:41:23gatojBasic L14-27
2018-12-01 20:49:29gatojBasic L13-25
2018-12-01 19:00:52gatojBasic L12-23
2018-12-01 18:36:40gatojBasic L11-21
2018-12-01 18:28:08gatojBasic L10-19
2018-11-30 15:28:051Basic L10-19
2018-11-30 11:23:22zhsks21c@naver.comBasic L18-35
2018-11-30 11:19:3412Basic L071213
2018-11-30 10:55:1612Basic L061211
2018-11-29 17:37:35LRTKBasic L05-9
2018-11-29 16:42:07LRTKBasic L04-7
2018-11-29 00:28:11LRTKBasic L03-5
2018-11-28 23:52:05LRTKBasic L02혹시 Basic RCE 2번 문제 복구 가능하나요??ㅠㅠ 가능하면 os424@naver.com 으로 알려주세요 ㅠㅠ3
2018-11-28 23:03:48LRTKBasic L01-1
2018-11-28 20:52:38zhsks21c@naver.comBasic L17-33
2018-11-28 20:06:34zhsks21c@naver.comBasic L16-31